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6p^2-12p-90=0
a = 6; b = -12; c = -90;
Δ = b2-4ac
Δ = -122-4·6·(-90)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-48}{2*6}=\frac{-36}{12} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+48}{2*6}=\frac{60}{12} =5 $
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